ZipArchive::getStream
ZipArchive::getStream
(PHP 5 >= 5.2.0, PHP 7, PECL zip >= 1.1.0)
ZipArchive::getStream - 获取文件处理程序到由其名称定义的条目（只读）。
描述
resource ZipArchive::getStream ( string $name )
获取文件处理程序到由其名称定义的条目。目前它只支持读取操作。
参数
name
要使用的条目的名称。
返回值
成功返回文件指针（资源）或失败时返回FALSE的。
示例
Example #1 Get the entry contents with fread() and store it
<?php
$contents = '';
$z = new ZipArchive(
if ($z->open('test.zip')) {
$fp = $z->getStream('test'
if(!$fp) exit("failed\n"
while (!feof($fp)) {
$contents .= fread($fp, 2
}
fclose($fp
file_put_contents('t',$contents
echo "done.\n";
}
?>
Example #2 Same as the previous example but with fopen() and the zip stream wrapper
<?php
$contents = '';
$fp = fopen('zip://' . dirname(__FILE__) . '/test.zip#test', 'r'
if (!$fp) {
exit("cannot open\n"
}
while (!feof($fp)) {
$contents .= fread($fp, 2
}
echo "$contents\n";
fclose($fp
echo "done.\n";
?>
Example #3 Stream wrapper and image, can be used with the xml function as well
<?php
$im = imagecreatefromgif('zip://' . dirname(__FILE__) . '/test_im.zip#pear_item.gif'
imagepng($im, 'a.png'
?>
← ZipArchive::getStatusString
ZipArchive::locateName →
